Rabu, 10 Juni 2009

Tugas UTS digital

1. A= 3F16

B= 5C16

Y1 = A + B

Y2 = A B

Y3 = A . B

JAWAB:

A = 3F

= 3x161 + F(15)x 160

= 48 + 15

= 6310 = 1 1 1 1 1 12

B = 5C

= 5x161 + C(12)x160

= 80 + 12

= 9210 = 1 0 1 1 1 0 02

A

B

Y1 = A+ B

Y2 = A B

Y3= A . B

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1

1

0

1

1

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Y1 = (1 x 26) + (1 x 25) + (1 x 24) + (1 x 23) + (1 x 22) + (1 x 21) + (1 x 20)

= 64 + 32 + 16 + 8 + 4 + 2 +1

= 12710 = 7F16

Y2 = (1x26)+(1x25)+(0x24)+(0x23)+(0x22)+(1x21)+(1x20)

= 64 + 32 + 0 + 0 + 0 + 2 + 1

= 9910 = 6316

Y3 = (0x26)+(0x25)+(1x24)+(1x23)+(1x22)+(0x21)+(0x20)

= 0+0+16+8+4+0+0

= 2810 =1C16

2. A= 3C

B = 5F

X1=A+B

X2=A – B

JAWAB:

A= 3x161+C(12)x160

= 48 +12

=6010 = 1 1 1 1 0 02

B=5x161+F(15)x160

=80 +15

=9510 = 10111112

X1 =A + B

A = 0 1 1 1 1 0 0

B = 1 0 1 1 1 1 1 +

S = 1 0 0 1 1 0 1 12

= 15510

= 9B16

X2 =A – B

B’ = 0 1 0 0 0 0 0

1 +

= 0 1 0 0 0 0 1

A = 0 1 1 1 1 0 0

B’= 0 1 0 0 0 0 1 +

S = 1 0 1 1 1 0 1

3. 516 = 5 x 16 = 8010 = 1 0 1 0 0 0 02

616 = 6 x 16 = 9610 = 1 1 0 0 0 0 02

716 = 7 x 16 = 11210 =1 1 1 0 0 0 02

816 = 8 x 16 = 12810 =1 0 0 0 0 0 0 02